Question

X2+4x+1=0 решите пж ок да

Answer 1

${x}^{2} + 4x + 1 = 0$
$D = {4}^{2} - 4 = 12 \\ x(1) = \frac{- 4 + \sqrt{12}}{2} = - 2 + \sqrt{3} \\ x(2) = - 2 - \sqrt{3}$