Question

По теореме виет 67х2-105х+38=0

Answer 1

67x²-105x+38=0

x1+x2= 105/67

x1*x2= 38/67

x1=105/67-x2

(105/67-x2)*x2=38/67      

((105-67x2)/67)*x2=38/67     I*67

105x2-67x2²=38

67x2²-105x2+38=0

D= 11025- 10184= 841

(x2)1= (105-29)/134= 76/134= 38/67

(x2)2= (105+29)/134= 1

Проверяем:

(x1)1= 105/67-38/67= 1

(x1)2= 105/67-1 = 38/67

Корни: 1 и 38/67