Question

log1/3(2x+1)=3
Помогите подалуйстаааа

Answer 1

ОДЗ: 2х + 1 > 0 <=> х > - 0,5


$log_{ \frac{1}{3} }(2x + 1) = 3 \\ \\ log_{ \frac{1}{3} }(2x + 1) = log_{ \frac{1}{3} }( \frac{1}{27} ) \\ \\ 2x + 1 = \frac{1}{27} \\ 2x = \frac{1}{27} - 1 \\ 2x = - \frac{ 26}{27} \\ x = - \frac{13}{27}$


ОТВЕТ: - 13/27