Question

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Log5(2x+3)=log5(x+1)

Answer 1

$log_5(2x+3)=log_5(x+1)\; \; ,\\\\ODZ:\; \left \{ {{2x+3>0} \atop {x+1>0}} \right. \; \left \{ {{x>-1,5} \atop {x>-1}} \right. \; \; \Rightarrow \; \; \underline {x>-1}\\\\2x+3=x+1\\\\2x-x=1-3\\\\x=-2<-1\; \; \Rightarrow \; \; \underline {x\in \varnothing }\\\\Otvet:\; \; reshenij\; net\; .$