Question

Решите неравенство log8(5-2x)>1

Answer 1

$log_8(5-2x)>1\; ,\; \; \; ODZ:\; 5-2x>0\; ,\; x<2,5\\\\5-2x>8\\\\2x<-3\\\\x<-1,5\\\\\left \{ {{x<2,5} \atop {x<-1,5}} \right. \; \; \; \; \Rightarrow \; \; \; \; \underline {x<-1,5}$

Answer 2

$log_{8}(5 - 2x) > 1 \\ {8}^{1} > 5 - 2x \\ - 2x < 8 - 5 \\ - 2x < 3 \\ x > - \frac{3}{2}$