Question

5х в квадрате +8х+3=0

Answer 1

$5x {}^{2} + 8x + 3 = 0 \\ d = 8 \times 8 - 4 \times 5 \times 3 = 64 - 60 = 4 \\ \sqrt{d} = 2 \\ x1 = \frac{ - 8 + 2}{ 10} = \frac{ - 6}{10} = \frac{ - 3}{5} \\ x2 = \frac{ - 8 - 2}{10} = \frac{ - 10}{10} = - 1$

Answer 2

5x^2+8x+3=0

D=8^2+4*5*3=4=2^2

X1=(-8-2)/10=-1

X1=(-8+2)/10=-0,6