Question

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(d^18+u^18)^2−(d^18−u^18)^2−d^2u^2

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Answer 1

$(d^{18}+u^{18})^2-(d^{18}-u^{18})^2-d^2u^2=$

$d^{36}+2d^{18}u^{18}+u^{36}-(d^{36}-2d^{18}u^{18}+d^{36})-d^2u^2=$

$d^{36}+2d^{18}u^{18}+u^{36}-d^{36}+2d^{18}u^{18}-d^{36}-d^2u^2=$

$2d^{18}u^{18}+2d^{18}u^{18}-d^2u^2=$

$4d^{18}u^{18} - d^2u^2$