Question

решить неравенство (2/7)^x^2 больше (3.5)^x-2

Answer 1

${( \frac{2}{7} )}^{ {x}^{2} } > ({ \frac{35}{10} )}^{x - 2} \\ {( \frac{2}{7} )}^{ {x}^{2} } > ({ \frac{7}{2} )}^{x - 2} \\ {( \frac{2}{7} )}^{ {x}^{2} } > ({ \frac{2}{7} )}^{2 - x} \\ {x}^{2} < 2 - x \\ x {}^{2} + x - 2 < 0 \\ x = 1 \\ x = - 2 \\ ( - \infty . - 2) (1. + \infty )$