Предмет: Химия, автор: волчонок732

выясните объем (н. у.) кислорода необходимый для окисления 3,1 грамма фосфора

Ответы

Автор ответа: inna15tkachenko

1

3,1 г/31г/моль=0,1 моль(Р)

4Р+5О2=2Р2О5

Для 4 моль Р - 5 моль О2

Для 0,1 моль Р - х

Х=0,125

0,125моль*22,4л/моль=2,8л кисню

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