Question

Помогите упростить пример

Answer 1

$......=\frac{b+2}{(b-1)(b-1)} *\frac{3(b-1)}{(b-2)(b+2)} -\frac{3}{b-2} =\\ \\ \frac{3}{(b-1)(b-2)} -\frac{3}{b-2}=\frac{3-3(b-1)}{(b-1)(b-2)} =\frac{3-3b+3}{(b-1)(b-2)} =\\ \\ \frac{6-3b}{(b-1)(b-2)} =\frac{3(2-b)}{(b-1)(b-2)} =\frac{-3(b-2)}{(b-1)(b-2)} =-\frac{3}{b-1}$