Question

Помогите решить: Sin(pi(2x-5)/4)=sqrt(2)/2

Answer 1

$\sin(\frac{\pi(2x - 5)}{4}) = \frac{\sqrt{2}}{2}\\\frac{\pi(2x - 5)}{4} = (-1)^n\frac{\pi}{4} + \pi n, n \in \mathbb{Z}\\x = \frac{(-1)^n + 4n + 5}{2}, n \in \mathbb{Z}$

Answer 2

Решение во вложении.