Question

cos2xsin2x = - √3/4
помогите решить

Answer 1

$Cos2xSin2x=-\frac{\sqrt{3}} {4}\\\\2Cos2xSin2x=-\frac{\sqrt{3}} {4}*2\\\\Sin4x=- \frac{\sqrt{3}} {2}\\\\4x=(-1) ^{n}arcSin(- \frac{\sqrt{3}} {2})+ \pi n\\\\4x=(-1)^{n+1} \frac{\pi} {3} +\pi n\\\\x=(-1)^{n+1} \frac{\pi} {12}+ \frac{\pi n} {4}$

Везде добавить n ∈ z