Question

Решите уравнение:



12y²+16y-3=0


2у²-5у-3=0

Answer 1

Ответ:

Объяснение:

1) 12y^2 + 16y - 3 = 0

D/4 = 8^2 - 12(-3) = 64 + 36 = 100 = 10^2

y1 = (-8 - 10)/12 = -18/12 = -3/2

y2 = (-8 + 10)/12 = 2/12 = 1/6

2) 2y^2 - 5y - 3 = 0

D = 5^2 - 4*2(-3) = 25 + 24 = 49 = 7^2

y1 = (5 - 7)/4 = -2/4 = -1/2

y2 = (5 + 7)/4 = 12/4 = 3