Question

найдите производные функции:а)f(x)=2x^6-4/x^2; б)f(x)=(2√x+1)*x^3

Answer 1

$(2x^6-4/x^2)'=(2x^6)'-(4/x^2)'=2*6*x^5-4*(-2)/x^3=12x^5+8/x^3$

$[(2*\sqrt{x}+1)*x^3]'=[2*x^(3\frac{1}{2}) +x^3]'=2*(3\frac{1}{2})x^(2\frac{1}{2})+3*x^2=3*x^2(\sqrt{x} +1)$