Question

спасибо большое... заранее

Answer 1

(1/(x + 5) + 10/(x^2 - 25))•(x - 5)

ОДЗ: x + 5 <> 0, x^2 - 25 <> 0
x + 5 <> 0, (x - 5)(x + 5) <> 0
(x - 5)(x + 5) <> 0
x <> -5, x <> 5

(1/(x + 5) + 10/(x^2 - 25))•(x - 5) = (1/(x + 5) + 10/((x - 5)(x + 5)))•(x - 5) = (x - 5 + 10)/((x - 5)(x + 5))•(x - 5) = (x + 5)(x - 5)/((x - 5)(x + 5)) = 1