Question

-15х+(6х во 2 степени) =2 решите уравнение!

Answer 1

Решение во вложении...

Answer 2

$-15x+(6x^2)=2\\ 6x^2-15x-2=0\\D=b^2-4ac=225+48=273\\x1=\frac{-b-\sqrt{D}} {2a}=\frac{15-\sqrt{273}} {12}\\x2=\frac{-b+\sqrt{D}} {2a}=\frac{15+\sqrt{273}} {12}$

Ответ: $x1=\frac{15-\sqrt{273}} {12}\\x2=\frac{15+\sqrt{273}} {12}$