Question

Вычислить Log3 27;log4 1;log1/2 4;6log6 13

Answer 1

1. log(3; 27)=3

3^x=27

x=27

2. log(4; 1)=0

4^x=1

x=0

3. log(1/2; 4)=-2

(1/2)^x=4

x=-2

4. 6log(6; 13)=6*ln13/ln6=(6*ln13)/(ln2+ln3)