Question

Решить систему
4x^2+4xy+y^2=25
2x-y=3

Answer 1

$\left \{ {{4x^{2}+4xy+y^{2}=25}\atop {2x-y=3}} \right.\\\\\left \{ {{(2x+y)^{2}=25} \atop {2x-y=3}} \right.\\\\1)+\left \{ {{2x+y=5} \atop {2x-y=3}} \right.\\\\4x=8\\x_{1}= 2\\y_{1} =5-2x=5-2*2=5-4=1\\\\2) +\left \{ {{2x+y=-5} \atop {2x-y=3}} \right.\\\\4x=-2\\x_{2}= -0,5\\y_{2}=-2x-5=-2*(-0,5)-5=1-5=-4$

Ответ : (2 ; 1) , (- 0,5 ; - 4)