Question

помогите пж !!!!!!!!!!!!!!!!!

Answer 1

$\sqrt{ \frac{2x + 1}{x - 2} } - 3 \sqrt{ \frac{x - 2}{2x + 1} } + 2 = 0 \\ t = \frac{2x + 1}{x - 2} \\ \sqrt{t} - 3 \sqrt{ \frac{1}{t} } + 2 = 0 \\ t = 1 \\ \frac{2x + 1}{x - 2} \\ x = - 3 \\ \sqrt{ \frac{2 \times ( - 3) + 1}{ - 3 - 2} } - \sqrt{ \frac{ - 3 - 2}{2 \times ( - 3) + 1} } + 2 = 0 \\ 0 = 0 \\ x = - 3$
Ответ: -3