Question

помогите пж под в , срочно , плиз хелп ми!

Answer 1

$\sqrt{ \frac{2x + 1}{x - 2} } - 3 \sqrt{ \frac{x - 2}{2x + 1} } + 2 = 0 \\ t = \frac{2x + 1}{x - 2} \\ \sqrt{t} - 3 \sqrt{ \frac{1}{t} } + 2 = 0 \\ \sqrt{t} - 3 { \frac{1}{ \sqrt{t} } + 2 } = 0 \\ \sqrt{t} - \frac{3}{ \sqrt{t} } + 2 = 0 \\ \frac{t - 3 + 2 \sqrt{t} }{ \sqrt{t} } = 0 \\ t - 3 + 2 \sqrt{t} = 0 \\ t + 2 \sqrt{t} - 3 = 0 \\ t^{2} + 2t - 3 = 0 \\ \sqrt{t} = - 3 \\ \sqrt{t} = 1 \\ t = 1 \\ \frac{2x + 1}{x - 2} \\ x = - 3 \\ \sqrt{ \frac{2 \times ( - 3) + 1}{ - 3 - 2} } - \sqrt{ \frac{ - 3 - 2}{2 \times ( - 3) + 1} } + 2 = 0 \\ 0 = 0 \\ x = - 3$
Ответ: -3