Question

Решите уравнение x(x^2+4x+4)=3(x+2)

Answer 1

$x(x^2+4x+4)=3(x+2)\\x(x+2)^2=3(x+2)\\x(x+2)^2-3(x+2)=0\\\left(x+2\right)\left(x\left(x+2\right)-3\right)=0\\x+2=0\Rightarrow \boxed{x_1=-2}\\x(x+2)-3=0\\x^2+2x-3=0\\D_1=1^2-1\cdot(-3)=4\\x_2=-1-2\Rightarrow \boxed{x_2=-3}\\x_3=-1+2\Rightarrow \boxed{x_3=1}$

Ответ: -3; -2; 1