Question

решите квадратные уравнения

Answer 1

$1) - 2 {x}^{2} + 5x + 3 = 0 \\ d = {5}^{2} - 4 \times ( - 2) \times 3 = 25 + 24 = 49 \\ x1 = \frac{ - 5 + 7}{ - 4} = - 0.5 \\ x2 = \frac{ - 5 - 7}{ - 4} = 3$
$2) {x}^{2} - 5x + 3 = 0 \\ d = 25 - 4 \times 1 \times 3 = 13 \\ x1 = \frac{5 + \sqrt{13} }{2} \\ x2 = \frac{5 - \sqrt{13} }{2}$