Question

√(x-4√(x+1)+5)+√(x+4√(x+1)+5)=4
Помогите

Answer 1

ОДЗ

x+4≥0⇒x≥-4

x-1≥0⇒x≥1

x-4≥0⇒x≥4

x∈[4;∞)

x+4-2√(x²+3x-4)+x-1=x-4

2√(x²+3x-4)=x+7

4x²+12x-16-x²-14x-49=0

3x²-2x-65=0

D=4+780=784

x1=(2-28)/6=-13/3∉ОДЗ

х2=(2+28)/6=5