Предмет: Алгебра,
автор: Аноним
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Здесь больше , на ту задачу дополнение ![frac{3a+d}{2a-5d}-frac{7a+5d}{a+3d}=frac{(3a+d)(3d+a)-(7a+5d)(2a-5d)}{(2a-5d)(a+3d)}=frac{28d^2+35ad-11a^2}{-15d^2+ad+2a^2}\
frac{4a-4z}{4d-z}-frac{4d-6z}{6d-6z}=frac{24(d-z)^2-(4d-6z)(4d-z)}{(4d-z)(6d-6z)} = frac{18z^2-20dz+8d^2}{6z^2-30dz+24d^2}\
frac{3x-y}{3x+4y}-frac{5x+2y}{3x+4y}=frac{-2x-3y}{3x+4y}\
frac{1-2c}{7-5c}-1=frac{3c-6}{7-5c}\
frac{2a^2+4ab-6b^2}{a^2-5ab+6b^2}\
frac{4b+2m}{8b+6m}-frac{3b+2m}{8b+6m}=frac{b}{8b+6m}\
frac{3a-6}{3a-4}-frac{2a+2}{3a-4}=frac{a-8}{3a-4}\](https://tex.z-dn.net/?f=frac%7B3a%2Bd%7D%7B2a-5d%7D-frac%7B7a%2B5d%7D%7Ba%2B3d%7D%3Dfrac%7B%283a%2Bd%29%283d%2Ba%29-%287a%2B5d%29%282a-5d%29%7D%7B%282a-5d%29%28a%2B3d%29%7D%3Dfrac%7B28d%5E2%2B35ad-11a%5E2%7D%7B-15d%5E2%2Bad%2B2a%5E2%7D%5C%0Afrac%7B4a-4z%7D%7B4d-z%7D-frac%7B4d-6z%7D%7B6d-6z%7D%3Dfrac%7B24%28d-z%29%5E2-%284d-6z%29%284d-z%29%7D%7B%284d-z%29%286d-6z%29%7D+%3D+frac%7B18z%5E2-20dz%2B8d%5E2%7D%7B6z%5E2-30dz%2B24d%5E2%7D%5C%0Afrac%7B3x-y%7D%7B3x%2B4y%7D-frac%7B5x%2B2y%7D%7B3x%2B4y%7D%3Dfrac%7B-2x-3y%7D%7B3x%2B4y%7D%5C%0Afrac%7B1-2c%7D%7B7-5c%7D-1%3Dfrac%7B3c-6%7D%7B7-5c%7D%5C%0Afrac%7B2a%5E2%2B4ab-6b%5E2%7D%7Ba%5E2-5ab%2B6b%5E2%7D%5C%0Afrac%7B4b%2B2m%7D%7B8b%2B6m%7D-frac%7B3b%2B2m%7D%7B8b%2B6m%7D%3Dfrac%7Bb%7D%7B8b%2B6m%7D%5C%0Afrac%7B3a-6%7D%7B3a-4%7D-frac%7B2a%2B2%7D%7B3a-4%7D%3Dfrac%7Ba-8%7D%7B3a-4%7D%5C%0A%0A "frac{3a+d}{2a-5d}-frac{7a+5d}{a+3d}=frac{(3a+d)(3d+a)-(7a+5d)(2a-5d)}{(2a-5d)(a+3d)}=frac{28d^2+35ad-11a^2}{-15d^2+ad+2a^2}\
frac{4a-4z}{4d-z}-frac{4d-6z}{6d-6z}=frac{24(d-z)^2-(4d-6z)(4d-z)}{(4d-z)(6d-6z)} = frac{18z^2-20dz+8d^2}{6z^2-30dz+24d^2}\
frac{3x-y}{3x+4y}-frac{5x+2y}{3x+4y}=frac{-2x-3y}{3x+4y}\
frac{1-2c}{7-5c}-1=frac{3c-6}{7-5c}\
frac{2a^2+4ab-6b^2}{a^2-5ab+6b^2}\
frac{4b+2m}{8b+6m}-frac{3b+2m}{8b+6m}=frac{b}{8b+6m}\
frac{3a-6}{3a-4}-frac{2a+2}{3a-4}=frac{a-8}{3a-4}\")
![frac{x}{1-x}-frac{(1-x)(1+x)}{1+x^2}*(frac{1}{(x-1)^2}-frac{x}{1-x^2})=frac{x}{1-x}-frac{1}{1-x}=frac{x-1}{1-x}=-1\
frac{5c-6b}{c+6b}+frac{6c-2b}{c+6b}=frac{11c-8b}{c+6b}](https://tex.z-dn.net/?f=frac%7Bx%7D%7B1-x%7D-frac%7B%281-x%29%281%2Bx%29%7D%7B1%2Bx%5E2%7D%2A%28frac%7B1%7D%7B%28x-1%29%5E2%7D-frac%7Bx%7D%7B1-x%5E2%7D%29%3Dfrac%7Bx%7D%7B1-x%7D-frac%7B1%7D%7B1-x%7D%3Dfrac%7Bx-1%7D%7B1-x%7D%3D-1%5C%0Afrac%7B5c-6b%7D%7Bc%2B6b%7D%2Bfrac%7B6c-2b%7D%7Bc%2B6b%7D%3Dfrac%7B11c-8b%7D%7Bc%2B6b%7D "frac{x}{1-x}-frac{(1-x)(1+x)}{1+x^2}*(frac{1}{(x-1)^2}-frac{x}{1-x^2})=frac{x}{1-x}-frac{1}{1-x}=frac{x-1}{1-x}=-1\
frac{5c-6b}{c+6b}+frac{6c-2b}{c+6b}=frac{11c-8b}{c+6b}")
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