Question

квадратное уравнение с модулем
$x^{2} + |x| =7/4$

Answer 1

x^2+x-7/4=0
4x^2+4x-7=0
x=[-2+-sqrt(32)]/4=-2+-4sqrt(2)]/4=-0,5+-sqrt(2)
x1=sqrt(2)-1/2
x<0
x^2-x-7/4=0
4x^-4x-7=0
x=1/2+-sqrt(2)
x2=1/2-sqrt(2)