Question

Решите уравнение! 20 баллов!!

Answer 1

$log_{ \frac{1}{2} }( - x) = y$
$6y - 4 {y}^{2} - 2 = 0$
$4 {y}^{2} - 6y + 2 = 0 \\ 2 {y}^{2} - 3y + 1 = 0 \\ y = \frac{1}{2} \\ y = 1$
$log_{ \frac{1}{2} }( - x) = 1 \\ x = - \frac{1}{2}$
$log_{ \frac{1}{2} }( - x) = \frac{1}{2} \\ x = - \frac{ \sqrt{2} }{2}$