Question

(c^3/c^2-8c+16) - (c^2/c-4)

Answer 1

$\frac{ {c}^{3} }{ {(c - 4)}^{2} } - \frac{ {c}^{2} }{(c - 4)} = \\ \frac{ {c}^{3} - {c}^{2} (c - 4) }{ {(c - 4)}^{2} } =$
$\frac{ {c}^{3} - {c}^{3} + 4 {c}^{2} }{ {(c - 4)}^{2} }$