Question

497!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

$(1-x)(4x^2+2x-+1)+8x^3=\\=4x^2+2x+1-8x^3-4x^2-2x+8x^3 = 1\\\\(9-6a+4a^2)(2a+3)-8a^3=\\=18a+27-12a^2-18a+8a^3+12a^2-8a^3 =27\\\\(2a+3x)(4x^2-6ax+9x^2)-27x^3=\\=8a^3+27x^3-27x^3=8a^3\\\\(3-c^2)(c^4-3c^2+9)+c^6-27=\\=3c^4-9c^2+27-c^6+3c^4-9c^2+c^6-27=6c^4-18c^2$