Question

решите плиииииииз сложнааа

Answer 1

$\sqrt{2x + 3} = x \\ 2x + 3 = {x}^{2} \\ {x}^{2} - 2x - 3 = 0 \\ x1 = 3 \\ x2 = - 1$
$\sqrt{2x + 1} = x - 1 \\ 2x + 1 = {x}^{2} - 2x + 1 \\ {x}^{2} - 4x =0 \\ x(x - 4) = 0 \\ x1 = 0 \\ x2 = 4$