Question

Помогите 5(3-2a)+3(49-5) при:a 3,5.
(3x)-(2-4x)+(4+3x) при:x 0,1234

Answer 1

1)15-10a+147-15=-10a+147=-10*3,5+147=35+147=182
2)3x-2+4x+4+3x=3*0,1234-2+4*0,1234+4+3*0,1234=3,234

Answer 2

$1) \: 5 \times (3 - 2 \times 3.5) + 3 \times (49 - \\ - 5 \times 3.5) = 5 \times( 3 - 7) + 49 - \\ - 5 \times 3.5 = 5 \times ( - 4) + 49 - \\ - 5 \times 3.5 = - 20 + 49 - 17.5 = \\ = 29 - 17.5 = 11.5$
$2) \: (3 \times 0.1234) - (2 - 4 \times \\ \times 0.1234) + (4 + 3 \times 0.1234) = \\ = 0.3702 - 1 \times 1.5064 + 4 + \\ + 3 \times 0.1234 = 0.3702 - 1.5064 + 4 \\ + 0.3702 = - 1.1362 + 0.3702 = \\ = 3.234$