Question

решите пожалуйста, дам 15 баллов

Answer 1

${x}^{2} + \frac{1}{ {x}^{2} } = 6 \\ (x - \frac{1}{x} )^{2} = {x}^{2} - \frac{2}{x} + \frac{1}{ {x}^{2} } = 6 - \frac{2}{x} \\ 6 = \frac{2}{x} \\ x = \frac{1}{3} \\ x - \frac{1}{x} = \frac{1}{3} - \frac{1}{ \frac{1}{3} } = \frac{1}{3} - 3 = - 2 \frac{2}{3}$