Question

Найти производную функции у= ln arcsinx+xe^x

Answer 1

$y' = (ln(arcsin(x)) + xe^{x} )' = (ln(arcsin(x)))'+(xe^{x})' = \frac{1}{arcsin(x)}*(arcsin(x))'+x'e^{x}+(e^{x})'x = \frac{1}{\sqrt{1-x^2}arcsin(x)}+e^x+xe^x$