Question

РАЗЛОЖИТЕ НА МНОЖИТЕЛИ
$x^{8}+ x^{4}-2$

Answer 1

$x^8+x^4-2=0\t=x^4; ; to ; ; t^2+t-2=0; ,; t_1=-2; ,; t_2=1; ; to \(t-1)(t+2)=0\(x^4-1)(x^ +2)=0\(x^2-1)(x^2+1)(x^4+2)=0\(x-1)(x+1)(x^2+1)(x^4+2)=0; ; to \x^8+x^4-2=(x-1)(x+1)(x^2+1)(x^4+2)$