Question

Помогите! Решить при a/b=3.

Answer 1

$\frac{a}{b} = 3 \\ a = 3b$

$\frac{a + 9b + 16}{a + 3b + 8} = \frac{3b + 9b + 16}{3b + 3b + 8} = \frac{12b + 16}{6b +8 } = \\ = \frac{2(6b + 8)}{6b + 8} = 2$


ОТВЕТ: 2

Answer 2

$\frac{a}{b}=3\Rightarrow a=3b\Rightarrow \frac{a+9b+16}{a+3b+8}=\frac{12b+16}{6b+8} = \frac{2(6b+8)}{6b+8)}=2$

Ответ: 2