Question

Пожалуйста помогите решить эти примеры!! 20 баллов

Answer 1

$1)\frac{x-7}{2x+3} +\frac{x+5}{2x+3}= \frac{x-7+x+5}{2x+3}= \frac{2x-2}{2x+3}\\\\2)\frac{x-2}{5y}- \frac{y-2}{5y}= \frac{x-2-y+2}{5y}= \frac{x-y}{5y}\\\\3)\frac{3(4+2x)}{x-11}+1= \frac{12+6x+x-11}{x-11}= \frac{7x+1}{x-11}\\\\\\4)\frac{y-7}{2y}: \frac{y}{y+3}*\frac{y^{2}} {y+3}= \frac{y-7}{2y}* \frac{y+3}{y}* \frac{y^{2}} {y+3} = \frac{y-7}{2}$

$5)(\frac{(5-b)^{3}} {10b}) ^{2}= \frac{(5-b)^{6}} {100b^{2}}$

Answer 2

1. $\frac{x-7}{2x+3}+ \frac{x+5}{2x+3}= \frac{x-7+x+5}{2x+3}= \frac{2x-2}{2x+3}$

2. $\frac{x-2}{5y}- \frac{y-2}{5y} =\frac{x-2-y+2}{5y}= \frac{x-y}{5y}$

3. $\frac{3(4+2x)}{x-11} +1=\frac{12+6x}{x-11}+ \frac{x-11}{x-11}=\frac{12+6x+x-11}{x-11}= \frac{7x+1}{x-11}$

4. $\frac{y-7}{2y}: \frac{y}{y+3}* \frac{y^{2}}{y+3}=\frac{y-7}{2y}* \frac{y+3}{y}* \frac{y^{2}}{y+3}=\frac{y^{2}(y-7)(y+3)}{2y^{2}(y+3)}= \frac{y-7}{2}$

5. $(\frac{(5-b)^{3}}{10b})^{2}= \frac{(5-b)^{6}}{100b^{2}}$