Question

Решите пожалуйста...Нужно упростить выражение!!!

Answer 1

$1)\frac{y+3}{y-3}+ \frac{y^{2}} {9-y^{2}}= \frac{y+3}{y-3}- \frac{y^{2}} {(y-3)(y+3)} = \frac{y^{2}+3y+3y+9-y^{2}}{(y-3)(y+3)}= \frac{6y+9}{(y-3)(y+3)}= \frac{3(2y+3)}{(y-3)(y+3)}\\\\2)\frac{y+3}{2y+3}* \frac{3(2y+3)}{(y-3)(y+3)}= \frac{3}{y-3}$