Question

Помогите Пожалуйста!

Answer 1

$(9x^{4}) ^{2}*( \frac{1}{2} x^{5}) ^{8}=( \frac{3}{4}) ^{4} \\\\81x^{8}* \frac{1}{256} x^{40}= \frac{81}{256}\\\\\frac{81}{256} x^{48}= \frac{81}{256}\\\\x^{48}=1\\\\ x_{1} =1\\\\x_{2}=-1$