Question

12-(1-6x)x=3x(2x-1)+x
1,5-0,2(2x-1)=3+(0,6x-1,3)
Прошу и решение,заранее спасибо

Answer 1

$12 - x + 6 {x}^{2} = 6 {x}^{2} - 3x + x \\ - x + 3x - x = - 12 \\ x = - 12$
$1.5 - 0.4x + 0.2 = 3 + 0.6x - 1.3 \\ - 0.4x - 0.6x = 3 - 1.3 - 1.5 - 0.2 \\ - x = 0 \\ x = 0$

Answer 2

12-(1-6x)x=3x(2x-1)+x

12-(x-6x²)=6x²-3x+x

12-x+6x²=6x²-2x

12-x=-2x

2x-x=-12

x=-12

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1,5-0,2(2x-1)=3+(0,6x-1,3)

1,5-0,4x+0,2=3+0,6x-1,3

1,7-0,4x=1,7+0,6x

-0,4x-0,6x=1,7-1,7

-x=0

x=0

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