Question

найти производные прошууку

Answer 1

$1)\; \; y=\frac{2x^3-1-sinx}{e^{x}+cos2}\\\\y'=\frac{(6x^2-cosx)(e^{x}+cos2)-(2x^3-1-sinx)\cdot e^{x}}{(e^{x}+cos2)^2}\; \; ,\; \; cos2=const\; \to \; (cos2)'=0\\\\2)\; \; y=log^4_3(5x-1)\\\\y'=4\, log^3_3(5x-1)\cdot \frac{5}{5x-1}=\frac{20}{5x-1}\cdot log_3^3(5x-1)$