Question

помогите, алгебра подготовка к ЕГЭ
$\sqrt[4]{(1 - 2x + {x}^{2})( {x}^{2} - 1)(x - 1) } \times \frac{ \sqrt[4]{x + 1} }{ {x}^{2} + 2x - 3}$
при
$- 1 \leqslant x \leqslant 0$

Answer 1

$\sqrt[4]{(1-2x+x^2)(x^2-1)(x-1)} *\frac{\sqrt[4]{x+1}}{x^2+2x-3} = \sqrt[4]{(x-1)^4*(x+1)}*\frac{\sqrt[4]{x+1}}{x^2+2x-3} = (x-1)*\frac{\sqrt{x+1}}{x^2+2x-3} = (x-1)*\frac{\sqrt{x+1}}{(x-1)(x+3)} = \frac{\sqrt{x+1}}{x+3}\\x = -1; \frac{\sqrt{x+1}}{x+3} = 0;\\x = 0; \frac{\sqrt{x+1}}{x+3} = \frac13$

[0; $\frac13$]