Question

избавьтечь от иррациональности в знаменателе отношения.

Answer 1

$\frac{3}{\sqrt{5}}=\frac{3*\sqrt{5}}{\sqrt{5}*\sqrt{5}}=\frac{3\sqrt{5}}{5}$

$\frac{5}{3\sqrt{2}}=\frac{5*\sqrt{2}}{3\sqrt{2}*\sqrt{2}}=\frac{5*\sqrt{2}}{3*2}=\frac{5\sqrt{2}}{6}\\\\\frac{12}{5\sqrt{3}}=\frac{12*\sqrt{3}}{5\sqrt{3}*\sqrt{3}}=\frac{12*\sqrt{3}}{5*3}=\frac{4\sqrt{3}}{5}\\\\\frac{10}{3\sqrt{5}}=\frac{10*\sqrt{5}}{3\sqrt{5}*\sqrt{5}}=\frac{10*\sqrt{5}}{3*5}=\frac{2\sqrt{5}}{3}\\\\\frac{14}{9\sqrt{2}}=\frac{14*\sqrt{2}}{9\sqrt{2}*\sqrt{2}}=\frac{14*\sqrt{2}}{9*2}=\frac{7\sqrt{2}}{9}$

$\frac{3}{2\sqrt{17}}=\frac{3*\sqrt{17}}{2\sqrt{17}*\sqrt{17}}=\frac{3*\sqrt{17}}{2*17}=\frac{3\sqrt{17}}{34}\\\\\frac{6}{\sqrt{21}}=\frac{6*\sqrt{21}}{\sqrt{21}*\sqrt{21}}=\frac{6*\sqrt{21}}{21}=\frac{2\sqrt{21}}{7}\\\\\frac{2}{3\sqrt{14}}=\frac{2*\sqrt{14}}{3\sqrt{14}*\sqrt{14}}=\frac{2*\sqrt{14}}{3*14}=\frac{\sqrt{14}}{3*7}=\frac{\sqrt{14}}{21}$