Question

Помогите пожалуйста решить 8 задание 1 и 2 варианта

Answer 1

$1) \left \{ {{log_3(x+y) = 2} \atop {9^{log_3\sqrt{x-y}}}=5} \right.\\\left \{ {{x+y = 9} \atop ({\sqrt{x-y})^{log_39}}=5}} \right. \\\left \{ {{x = 9-y} \atop {x-y = 5}} \right. \\\left \{ {{x = 7} \atop {y = 2}} \right. \\2) \left \{ {{log_2(x-y) = 3} \atop {4^{log_2\sqrt{x+y}} = 10}} \right. \\\left \{ {{x-y=8} \atop {(\sqrt{x+y})^{log_24}=10}} \right.\\\left \{ {{x = 8+y} \atop {x+y=10}} \right.  \\\left \{ {{x=9} \atop {y=1}} \right.$