Question

Решите производную.....

Answer 1

$g(t)=(t+4)\, \sqrt[3]{t}\\\\g'(t)=\sqrt[3]{t}+(t+4)\cdot \frac{1}{3}\cdot t^{-2/3}=\sqrt[3]{t}+\frac{t+4}{3\cdot \sqrt[3]{t^2}}\\\\\\f(u)=(2u-\sqrt{u})^2\\\\f'(u)=2\cdot (2u-\sqrt{u})\cdot (2-\frac{1}{2\sqrt{u}})$