Question

Решите производную.....

Answer 1

решение во вложении:

Answer 2

$f(x)=\frac{27\sqrt{x}+8x^2}{x\sqrt{x}}\\\\f'(x)=\frac{(27\cdot \frac{1}{2\sqrt{x}}+16x)\cdot x\sqrt{x}-(27\sqrt{x}+8x^2)\cdot \frac{3}{2}x^{\frac{1}{2}}}{(x\sqrt{x})^2}=\\\\=\frac{13,5x+16\sqrt{x^5}-40,5x-12\sqrt{x^5}}{x^3}=\frac{-27x+4\sqrt{x^5}}{x^3}=-\frac{27}{x^2}+\frac{4}{\sqrt{x}}$