Question

помогите пожалуйста решить

Answer 1

$7) sin(-\frac \pi6) - 2tg(- \frac \pi4) + cos(-\frac \pi3)-ctg(-\frac \pi 2) = -\frac 12 + 2 + \frac12 - 0 = 2\\8)cos^3(-\frac \pi 3) - ctg^3(-\frac \pi6) + sin^3(-\frac \pi 6) = \frac18 + \sqrt3 - \frac18 = \sqrt3$

Answer 2

$\sin( - \frac{\pi}{6} ) - 2tg( - \frac{\pi}{4} ) + \cos( - \frac{\pi}{3} ) - ctg( - \frac{ \pi}{2} ) = - \frac{1}{2} - 2*( - 1) + \frac{1}{2} - 0 = 2 \\ \\ \\ \\ \cos {}^{3} ( - \frac{\pi}{3} ) - ctg {}^{3} ( - \frac{\pi}{6} ) + \sin {}^{3} ( - \frac{\pi}{6} ) = \frac{1}{8} + \sqrt{3} - \frac{1}{8} = \sqrt{3}$