Question

arccos (-√3/2) чему ровна? помогите

Answer 1

$\boxed {arccos(-\alpha )=\pi -arccos\alpha }\\\\\\arccos(-\frac{\sqrt3}{2})=\pi -\underbrace {arccos\frac{\sqrt3}{2}}_{cos\frac{\pi }{6}=\frac{\sqrt3}{2}}=\pi -\frac{\pi }{6}=\frac{5\pi }{6}$