Question

УМОЛЯЮ ПОМОГИТЕ ПОЖАЛУЙСТА
ХЭЛП

Answer 1

$(\frac{5x+3y}{5x-3y} -\frac{25x^2+9y^2}{25x^2-9y^2} )*(\frac{1}{5x} -\frac{1}{3y})=\\(\frac{5x+3y}{5x-3y} -\frac{25x^2+9y^2}{(5x-3y)(5x+3y)} )*(\frac{3y}{5x3y} -\frac{5x}{5x3y})=\\(\frac{(5x+3y)(5x+3y)}{(5x-3y)(5x+3y)} -\frac{25x^2+9y^2}{(5x-3y)(5x+3y)} )*(\frac{3y-5x}{15xy})=\\(\frac{25x^2+30xy+9y^2-25x^2-9y^2}{(5x-3y)(5x+3y)}) *\frac{-(5x-3y)}{15xy}=\\\frac{30xy}{(5x-3y)(5x+3y)} *\frac{-(5x-3y)}{15xy}=\\\\\frac{-2}{5x+3y}$