Question

решить неравенство 4^(2х+1)+4^(2х-1)-4^2х=52

Answer 1

$4^{2x+1} + 4^{2x - 1} - 4^{2x} = 52\\4*4^{2x} + \frac{4^{2x}}{4} - 4^{2x} = 52\\\frac{13*4^{2x}}{4} = 52\\4^{2x} = 16 = 4^{2}\\2x = 2\\x = 1$

Answer 2

$4^{2x+1}+4^{2x-1}-4^{2x}=52$

$4^{2x-1}(4^2+1-4)=52$

$4^{2x-1}=4$

$2x-1=1$

$x=1$