Question

Помогите пожалуйста
1) 125^-4 : 25^3
2) 10^0 : 10^-3

Answer 1

$\frac{ {125}^{-4} }{ {25}^{3} } = \frac{ ({{5}^{3} )}^{-4} }{ {({5}^{2}) }^{3} } = \frac{ {5}^{3 \times (- 4) } }{ {5}^{2 \times 3} } = \frac{ {5}^{-12} }{ {5}^{6} } = {5}^{-12 - 6} = \\ \\ = {5}^{-18}$
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10^0:10^-3=10^0-(-3)=10^0+3=10^3=1000