Question

решите неравенства (x+1)(x-1)/x+4<0

Answer 1

$\frac{(x+1)(x-1)}{x+4}<0\\\\x+1=0\; ,\; x-1=0\; ,\; x+4=0\; \; \Rightarrow \; \; x_1=-1\; ,\; x_2=1\; ,\; x_3=-4\\\\znaki:\; \; \; \; ---(-4)+++(-1)---(1)+++\\\\x\in (-\infty ,-4)\cup (-1,1)$